0=(1-24)/x^2

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Solution for 0=(1-24)/x^2 equation: 


D( x )

x^2 = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

0 = (1-24)/(x^2) // - (1-24)/(x^2)

0-((1-24)/(x^2)) = 0

-((1-24)/(x^2)) = 0

23*x^-2 = 0 // : 23

x^-2 = 0

x należy do O

x belongs to the empty set

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